Question

using suitable identities find a) (7x+6y)2 b) 999²​

Answer 1

Answer:

a. Given : (7x+6y)^2

Identity : (a+b)2 = a2+2ab + b2

here a=7x & b=6y

∴ (7x+6y)2 = (7x)2 + (6y)2 + 2*(7x)*(6Y)

                 = 49x2 + 36y2 +84xy

b. Given : $999^{2}$ = $(1000-1)^{2}$

Identity - (a-b)^2 = a^2-2ab+b^2

Here a-1000 and b-1

∴ $(1000-1)^{2}$ = 1000^2 - 2*1000*1 + 1^2

                    = 1000000-2000+1

                    =998001

Answer 2

Answer:

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Step-by-step explanation:

Answer:

a. Given : (7x+6y)^2

Identity : (a+b)2 = a2+2ab + b2

here a=7x & b=6y

∴ (7x+6y)2 = (7x)2 + (6y)2 + 2*(7x)*(6Y)

= 49x2 + 36y2 +84xy

b. Given : 999^{2}999

2

= (1000-1)^{2}(1000−1)

2

Identity - (a-b)^2 = a^2-2ab+b^2

Here a-1000 and b-1

∴ (1000-1)^{2}(1000−1)

2

= 1000^2 - 2*1000*1 + 1^2

= 1000000-2000+1

=998001