Question

using suitable identities,find the values of 104×97. 2). 99^3​

Answer 1

Answer:

104x97

=(100+4)(100+(-3))

Using the identity

(x+a) (x+b) =x²+(a+b)x+ab

=100²+(4-3)100+4(-3)

=10000+100-12

=10100-12

=10988

99= 100- 1

99^3​= [100-1]^3​

Using the identity

(a-b)³=a³-b³-3a²b+3ab²

100³-1³-3(100²)1+3(100)1²

1000000-1-30000+30000

999999