using suitable identities,find the values of 104×97. 2). 99^3
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Answer:
104x97
=(100+4)(100+(-3))
Using the identity
(x+a) (x+b) =x²+(a+b)x+ab
=100²+(4-3)100+4(-3)
=10000+100-12
=10100-12
=10988
99= 100- 1
99^3= [100-1]^3
Using the identity
(a-b)³=a³-b³-3a²b+3ab²
100³-1³-3(100²)1+3(100)1²
1000000-1-30000+30000
999999
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