Question

using suitable identity ( -a/2+c/2 ) ( -a/2+c/2)
​

Answer 1

Step-by-step explanation:

(-a/2 + c/2)²

Identity will use :-

(a+b)² = a²+ b²+ 2ab

Therefore,

(-a/2)²+ (c/2)²+ [2×(-a/2)×(c/2)]

a²/4 + c²/4 + (-2ac/4)

a²/4 + c²/4 -ac/2

I hope it will help you