Using suitable identity evaluate 1001×998
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Hey mate!
Here is yr answer....
=> 1001 × 998
=> (1000+1) [1000+(-2)]
=> 1000² + [1+(-2)]1000 + (1)(-2)
=> 1000000 -1000 -2
=> 998998
Identity used :
[ x² + (a+b)x + ab]
Hope it helps u.....
#BeBrainly
Here is yr answer....
=> 1001 × 998
=> (1000+1) [1000+(-2)]
=> 1000² + [1+(-2)]1000 + (1)(-2)
=> 1000000 -1000 -2
=> 998998
Identity used :
[ x² + (a+b)x + ab]
Hope it helps u.....
#BeBrainly
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