Question

using suitable identity evaluate 101 * 102

Answer 1

Answer:

10302

Step-by-step explanation:

$101 \times 102$

This can also be written as

$(100 + 1) \times (100 + 2)$

Using identity

$(x + a)(x + b) = {x}^{2} + x(a + b) + ab$

x=100

a=1

b=2

${(100)}^{2} + 100(1 + 2) + (1 \times 2)$

$10000 + 300 + 2$

$= 10302$

Answer 2

Step-by-step explanation:

101×102

This can also be written as

(100 + 1) \times (100 + 2)(100+1)×(100+2)

Using identity

(x + a)(x + b) = {x}^{2} + x(a + b) + ab(x+a)(x+b)=x

2

+x(a+b)+ab

x=100

a=1

b=2

{(100)}^{2} + 100(1 + 2) + (1 \times 2)(100)

2

+100(1+2)+(1×2)

10000 + 300 + 210000+300+2

= 10302=10302