Question

using suitable identity evaluate 106^3-94^3

Answer 1

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Answer 2

Answer:

$\bf{(106)^3-(94)^3=(100-94)[106)^2+(106)(94)^2]}$

$\therefore\bf\pink{a^3-b^3=(a-b)(a^2+ab+b^2)]}$

$\bf{(12)[(100+6)^2+(100+6)(100-6)+(100-6)^2]}$

_____________________

$\rightarrow$12 {[(100)² + (6)² + 2(100)(6)] +

[(100)² - (6)²] + [(100)² + (6)² - 2(100)(6)]}

_____________________

•°• (a+b)² = a² + b² + 2ab, (a-b)²

= a² + b² -2ab, (a+b)(a-b) = a² - b²]

______________________

$\rightarrow$$\bf{12[3(100)^2+(6)^2]}$

$\rightarrow$$\bf{12[3(10000)+(36)]}$

$\rightarrow$$\bf{12(30000+36)}$

$\rightarrow$$\bf{12(30036)}$

$\rightarrow$$\bf\purple{360432}$