Using suitable identity evaluate 21×23
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Answer:
( 20 + 1 ) ( 20 + 3 )
using identity ( x + a ) ( x + b ) = x^2+( a + b )x+ ab
= ( 20 )^2 + (1 + 3 ) 20 + 1×3
= 400 + 80 + 3
= 483
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