Math, asked by kukutomar22, 7 months ago

Using suitable identity evaluate ( 2a - 7 ) ( 2a - 7 )

Answers

Answered by nyanza
23

Answer:

4a^2-14a+49

Step-by-step explanation:

(2a-7)(2a-7)=(2a-7)^2

(2a-7)^2=2a^2-(2a*7)+7^2

         =4a^2-14a+49

identity= (a-b)^2

Answered by Jaswindar9199
3

Given:

( 2a - 7 ) and ( 2a - 7 )

To Find:

( 2a - 7 ) ( 2a - 7 )

Solution:

Any value, say x, multipler by itself can be written as x^2.

Thus,

( 2a - 7 ) ( 2a - 7 ) can be written as (2a-7)^2.

The identity to be used is,

 {(a - b)}^{2}  =  {a - 2ab +  {b}^{2} }^{2}

 {(2a - 7)}^{2}  =  {(2a)}^{2}  - {2(2a)(7)} +  {7}^{2}

 {(2a - 7)}^{2}  = 4 {a}^{2}  - 28a + 49

The value of ( 2a - 7 ) ( 2a - 7 ) is 4a^2 - 28a + 49.

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