Question

Using suitable identity evaluate( -32)cube +(18)cube +(14) cube

Answer 1

Answer:

Step-by-step explanation:

let (-32) be x, (18) be y and (14) be z

so now the equation is (-32)³+(18)³+(14)³

=x³+y³+z³

we know that if x+y+z=0, then x³+y³+z³=3xyz

putting the value of x,y and z

(-32)+(18)+(14)

(-32)+18+14

(-32)+32

-32+32=0

so, now x³+y³+z³=3xyz

(-32)³+(18)³+(14)³=3*-32*18*14

                          =-24192

Answer 2

Step-by-step explanation:

2419 is the answer of these question