Math, asked by sanjaypadeyar99, 1 year ago

using suitable identity, evaluate (9.7)^2.

Answers

Answered by Anonymous
64
(10-0.3)^2 = 10^2 + (0.3)^2 - 2(10)(0.3) = 100 + 0.09 - 6 = 94.09

sanjaypadeyar99: yo
log6: which Identity you have used?
Anonymous: (a-b)^2 man... are you that mindless or what
Answered by dhwani1874
44

Answer:

9.7²=(10-0.3)

using (a-b)²=a²-2ab+b²

(10)²-2×10×0.3+(0.3)²

100-6+0.09

=94.09

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