Math, asked by angan5387, 1 year ago

using suitable identity expand (a + 2 b + 3 c) square​

Answers

Answered by Anonymous
12

 {(a + 2b + 3c)}^{2}  \\  =  {a}^{2}  +  {(2b)}^{2}  +  {(3c)}^{2}  + 2 \times a \times 2b + 2 \times (2b) \times 3c + 2 \times a \times 3c \\  =  {a }^{2}  + 4 {b}^{2}  + 9 {c}^{2}  + 4ab + 12bc + 6ac

Hope it will help you

Answered by basisthsingh1614bs
1

Answer:

4a²+b²+9c²+4ab-6bc-12ax

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