Question

using suitable identity expand
$(2x - 3y - 2z)^{2}$
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Answer 1

$(2x - 3y - 2z) {}^{2} \\ using \: identity \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (x + y + z) {}^{2}$

$| \leqslant < regards \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: akshat \: rajput \geqslant > |$

Answer 2

iii) (-2x+3y+2z)²

Using : (x+y+z)² = x² + y² + z² + 2xy + 2yz + 2xz
Here,
x = (-2x) , y = 3y , z = 2z

(-2x+3y+2z)² = (-2x)² + (3y)² + (2z)² + 2*(-2x)*3y + 2*3y*2z + 2*(-2x)*2z

= 4x² + 9y² + 4z² - 12xy + 12yz - 8xz

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