Question

Using suitable identity factorise 63a2 – 112b2​

Answer 1

Answer:

7(3a+4b)(3a−4b)

Step-by-step explanation:

63a2−112b2

=7(9a2−16b2)

=7[(3a)2−(4b)2]

Using, a2−b2=(a+b)(a−b)

=7(3a+4b)(3a−4b)(Answer )

Answer 2

Step-by-step explanation:

63a^2 - 112b^2

=7(9a^2 - 16b^2)

=7[(3a)^2 - (4b)^2]

using, a^2 - b^2 = ( a + b )( a - b)

=7(3a+4b)(3a−4b)

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