using suitable identity find 109 multiplied by 98
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Answered by
7
Answer:
109×98
(100+9)(100-2)
(100+9)(100+(-2))
id=(x+a)(x+b)=x square +(a+b)x +ab
x=100
a=9
b=(-2)
id=100×100+ (9+(-2))100+9×(-2)
=10000+(9-2)100-18
=10000+7×100-18
=10000+700-18
=10700-18
=10682
Answered by
1
Answer:
(1093)² - (98) 2 [16+16) 22 23 +1632 + (100 + 9)² - (100-2) 2 てのひ
(100)² +(99² +2x100x9 -(000)² + (2) ² - 2 21002² +81 +18,00 - 1100) ²-4 + 400 2x100x2
= 2200 + 73
2277
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