Math, asked by biswajit5195, 1 year ago

using suitable identity find 109 multiplied by 98

Answers

Answered by mehak362006
7

Answer:

109×98

(100+9)(100-2)

(100+9)(100+(-2))

id=(x+a)(x+b)=x square +(a+b)x +ab

x=100

a=9

b=(-2)

id=100×100+ (9+(-2))100+9×(-2)

=10000+(9-2)100-18

=10000+7×100-18

=10000+700-18

=10700-18

=10682

Answered by gadharinakul
1

Answer:

(1093)² - (98) 2 [16+16) 22 23 +1632 + (100 + 9)² - (100-2) 2 てのひ

(100)² +(99² +2x100x9 -(000)² + (2) ² - 2 21002² +81 +18,00 - 1100) ²-4 + 400 2x100x2

= 2200 + 73

2277

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