Math, asked by bushra90155, 1 month ago

using suitable identity find.
(i) (402)2
(ii) (901)2
(iii) (888)2​​

Answers

Answered by Sohamsiddu
1

Answer:

here you go

Step-by-step explanation:

1} (402)^2 = (400+2)^2

    W.K.T (a+b)^2 = a^2+2ab+b^2

 therefore (400^2) + 2(400)(2) + (2)^2

                  (160000) + (1600) + 4

                  = 161604

2} (901)^2 = (900-1)^2

    W.K.T (a-b)^2 = a^2-2ab+b^2

 therefore (900^2) - 2(900)(1) + (1)^2

                  (810000) + (1800) + 1

                  = 811801

2} (901)^2 = (800+88)^2

    W.K.T (a+b)^2 = a^2+2ab+b^2

 therefore (800^2) + 2(800)(88) + (88)^2

                  (640000) + (140800) + 7744

                  = 788544

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