using suitable identity find.
(i) (402)2
(ii) (901)2
(iii) (888)2
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1
Answer:
here you go
Step-by-step explanation:
1} (402)^2 = (400+2)^2
W.K.T (a+b)^2 = a^2+2ab+b^2
therefore (400^2) + 2(400)(2) + (2)^2
(160000) + (1600) + 4
= 161604
2} (901)^2 = (900-1)^2
W.K.T (a-b)^2 = a^2-2ab+b^2
therefore (900^2) - 2(900)(1) + (1)^2
(810000) + (1800) + 1
= 811801
2} (901)^2 = (800+88)^2
W.K.T (a+b)^2 = a^2+2ab+b^2
therefore (800^2) + 2(800)(88) + (88)^2
(640000) + (140800) + 7744
= 788544
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