Question

Using suitable identity find:

(i) 48²

(ii) 96²

(iii) 231²– 131²

(iv) 97 × 103

(v) 181²– 192= 162 × 200
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Answer 1

Answer:

(a+b)^2

(a+b)(a-b)=a^2+b^2

x^2(a+b)x+ab

These are the formulas you can use.

.............Thank You...............

Answer 2

Answer:

1.48^2

= (50-2)^2

=50^2 - 2*50*2+2^2

=2500-200+4

= 2300+4

= 2304

2.96^2

= (100-4)^2

= 100^2-2*100*4+4^2

= 10000- 800+16

=10000-816

=9184

3.231^2-131^2

=(231+131) (231-131)

= 362 * 100

=36200

4.97*103

= (100-3)(100+3)

= (100+3)(100-3)

= 100^2-3^2

= 10000-9

=9991