using suitable identity find the following product 107×98
Answers
Answered by
16
(100+9)(100+8)
100^2+100(9+8)+(9)(8)
10000+(100×17)+72
10000+1700+72
11,772
IDENTITY:-(X+a)(x+b)=x^2+x(a+b)+ab
mohita7:
thanks
your welcome
Answered by
20
Using Identity (X+a)(X+b)=
X^2+(a+b)X+ab.
We can break 107 as (100+7)
Again,98 as (100-2)
Here,
X=100
a=7
b=-2
so Now,
(100+7)(100-2)
=100^2+[(7+(-2)]100 +7×(-2)
=10000+5×100-14
= 500+9,986
=10,486
""" Plz mark as brainiest if u satisfied""
X^2+(a+b)X+ab.
We can break 107 as (100+7)
Again,98 as (100-2)
Here,
X=100
a=7
b=-2
so Now,
(100+7)(100-2)
=100^2+[(7+(-2)]100 +7×(-2)
=10000+5×100-14
= 500+9,986
=10,486
""" Plz mark as brainiest if u satisfied""
answer is 11,772
kk
his answer is wrong dear
noo
then how comes 100+9 and 100+8
formula
no,
kk
if ,100+9 then it will be 109 not 107
and another will become 108 instead of 98
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