Using suitable identity, find the product of (ii) Subtract 3l (4m-l+2n ) from 4l (3m+2n -2l)
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Answer:
Subtract 3l(l−4m+5n) from 4l(10n−3m+2l)
=4l(10n−3m+2l)−3l(l−4m+5n)
=(40ln−12lm+8l
2
)−(3l
2
−12lm+15ln)
=40ln−12lm+8l
2
−3l
2
+12lm−15ln
=25ln+5l
2
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Answer:
25ln + 5l2
so the answer is this you can write)write
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