Using suitable identity find value of 99X99
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★★★using suitable identity find the value of 90 x 90
✈︎✈︎> let's find out
✈︎✈︎using identity (I)
✈︎✈︎(a+b)=a²+2ab+b²
✈︎(90+9) (90+9)
✈︎(90+9)²= 90²+2(90)(9)+9²
✈︎(90+9)²= 8100+1620+81
✈︎(90+9)²= 9801
✈︎hence the value of 90×90 is 9801
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identities:-
(a+b)²=a²+2ab+b²
(a-b)²=a²-2ab+b²
(a+b)(a-b)=a²-b²
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