Using suitable identity, prove that
(0.87)^3 + (0.13)^3 / (0.87)^2 -(0.87*0.13) + (0.13)^2
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a^3 + b^3 = (a + b) * (a^2 - ab + b^2)
That's the factoring for the sum of 2 cubes.
So:
(0.87^3 + 0.13^3) / (0.87^2 - 0.87 * 0.13 + 0.13^2) =>
(0.87 + 0.13) * (0.87^2 - 0.87 * 0.13 + 0.13^2) / (0.87^2 - 0.87 * 0.13 + 0.13^2)
Simplify:
0.87 + 0.13 =>
1.00 =>
1
That's the factoring for the sum of 2 cubes.
So:
(0.87^3 + 0.13^3) / (0.87^2 - 0.87 * 0.13 + 0.13^2) =>
(0.87 + 0.13) * (0.87^2 - 0.87 * 0.13 + 0.13^2) / (0.87^2 - 0.87 * 0.13 + 0.13^2)
Simplify:
0.87 + 0.13 =>
1.00 =>
1
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