Using suitable identity prove that 0.87^3+0.13^3/0.87^2-(0.87*0.13)+0.13^2=1
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a+b)^3 formula I think so
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We will be using the identity,
(a^3+b^3)=(a+b)(a^2+b^2-ab)
Let 0.87=a,0.13=b.
Then ,a/q,
=>(a^3+b^3)/(a^2-ab+^2)
=>(a+b)(a^2-ab+b^2)/(a^2-ab+b^2)
=(a+b)=(0.87+0.13)=1.
Hope it helps
(a^3+b^3)=(a+b)(a^2+b^2-ab)
Let 0.87=a,0.13=b.
Then ,a/q,
=>(a^3+b^3)/(a^2-ab+^2)
=>(a+b)(a^2-ab+b^2)/(a^2-ab+b^2)
=(a+b)=(0.87+0.13)=1.
Hope it helps
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