using suitable identity solve( 1/2 x sqaure + 5 ) ( 1 /2 x sqaure + 3 )
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( 1/2 x sqaure + 5 ) ( 1 /2 x sqaure + 3 )
Identity: (y+a)(y+b)=y^2+(a+b)y+ab
=( 1/2 x sqaure)^2+(5+3)( 1/2 x sqaure)+5*3
=1/4x^4+4x sqaure+15
Identity: (y+a)(y+b)=y^2+(a+b)y+ab
=( 1/2 x sqaure)^2+(5+3)( 1/2 x sqaure)+5*3
=1/4x^4+4x sqaure+15
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