Question

Using suitable identity solve(2a-3b)square+((2a+3b)square

Answer 1

Answer:(2a -3b)^2 +(2a +3b)^2

using a^2 +b^2 =(a+b)^2 -2ab

=(2a-3b +2a +3b)^2 -2(2a-3b)(2a+3b)

using (a+b)(a-b)=a^2-b^2

=(4a)^2-2{(2a)^2-(3b)^2}

=16a^2-8a^2+18b^2

=8a^2+18b^2

Step-by-step explanation:

Answer 2

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${(2a3b)}^{2}+ {(2a+3b)}^{2}$

$(4{a}^{2}-12ab+9{b}^{2})+ (4{a}^{2}+12ab+9{b}^{2})$

$8{a}^{2}+18{b}^{2}$

Identity Used:

${(a+b)}^{2}= {a}^{2}+2ab+{b}^{2}$

${(a-b)}^{2}= {a}^{2}-2ab+{b}^{2}$

Hope it helps úh