using suitable identity solve the following (k+2)cube
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0
Answer:
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Answered by
5
Answer:
I think ur question is (k+2)³
(k+2)² (k+2)
=(k²+4+4k). (k+2)
=k(k²+4+4k) + 2(k²+4+4k
)
=k³+4k+4k+2k²+8+8k
=k³+16k+2k²+8
Explanation:
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