Question

using suitable identity value with the following (i) 101x102 (ii) 999². ???! ​

Answer 1

Answer:

$\large\boxed{\fcolorbox{blue}{yellow}answer}} [tex]{y {x}^{2} + 2yz} \: \: \: 2 {x}^{2} - yz$

Answer 2

Answer:

We have (999)

2

=(1000−1)

2

=(1000)

2

−2×(1000)×1+1

2

[ Using (a−b)

2

=a

2

−2ab+b

2

]

=100000−2000+1

=998001

hope it will help you