Question

using suitable laws of exponents simplify the following:{(-2/3)^- 2}^2 ​

Answer 1

Question :-- using suitable laws of exponents simplify the following:{(-2/3)^- 2}^2 ?

Formula used :--

→ Negative laws of exponents = (a)^(-n) = 1/a^n

→ (-a)² = a²

Solution :-

→ {(-2/3)^- 2}^2

→ { 1/(-2/3)² }²

→ { 1/ (4/9) }²

→ (9/4)²

→ 81/16 (Ans).

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Extra Brainly knowledge :-

→ x^1 = x

→ x^0 = 1

→ x^(-1) = 1/x

→ x^m*x^n = x^(m+n)

→ x^m/x^n = x^(m-n)

→ (x^m)^n = x^(mn)

→ (xy)^n = x^n*y^n

→ (x/y)^n = x^n/y^n

→ x^(-n) = (1/x)^n

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