using sutable identities(3x + 1)^3
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Answer:
(a+b)³=a³+b³+3a²b+3b²a
a=3x
b=1
(3x + 1)³=(3x)³+1³+3×(3x)²×1+3×1²3x
(3x + 1)³=27x³+1+27x²+9x
(3x + 1)³=27x³+27x²+9x+1
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