Question

Using tan(A+B)= tan A+tan B/1-tan A tan B , find the value of tan 75 where tan 45=1 and tan 30 =1/√3

Answer 1

hope this will help you.. friend

Answer 2

W e know that Tan(A + B) = (TanA + TanB)/(1-TanATanB)

 tan 75° = Tan(45°+ 30°) = (Tan45° + Tan30°)/(1-Tan 45° Tan30°)

tan 75° = (1 + 1 / √3 ) / (1 - 1 /√3)

tan 75° = (√3 + 1  ) / (√3 - 1 )

by rationalisation by (√3+1)

tan75° = (√3 + 1  )*(√3+1) / (√3 - 1 )*(√3 + 1  )

tan75°. = (4+2√3)/2 = (2+ √3)



Hope it helps