Math, asked by mahimaagrawal9027, 4 months ago

Using the appropriate properties of addition, find the value of each of the following sums:
(ii)4/5+3/10+11/5+(-13)/10
(iii) 2/3+(-11/8)+(-17)/3+3/8
(iv) 7/8+3/10+(-5/8)+(-7/20)


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Answers

Answered by bluemoon46
2

Answer:

use distributive propertie

Step-by-step explanation:

4/5+11/5+3/10+(-13)/10

=4/5+11/5+3/10+(-13/10)

=15/5+-10/10=

3+1=4

2/3+(-11/8+(-17)/3+3/8

=-15/3+8/8

=5+1=6

7/8+3/10+(-5/8)+(-7/20)

=7/8+(-5/8)+3/10+(-7/20)

=2/8+3/10+(-7/20)

=1/4+3/10+(-7/20)(take LCM of these)

1/4+(-4+2)

1/4+2=2/4=1/2

=2

Answered by radhikarss11
2

Step-by-step explanation:

(i)4\5+11\5+3\10+(-13)\10

=15\5+(-10)\10

=3+(-1)

=2

(ii)2\3+(-17)\3+(-11)\8+3\8

=-15\3+(-8)\8

=-5+(-1

=-5-1

=-4

(iii)7\8+(-5)\8+3\10+(-7)\20

=2\8+2×3\10+(-7)\20

=2\8+6\20+(-7)\20

=1\8+(-1)\20

=1\8-1\20

=20-8\160

=12\180

=0.066

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