Question

Using the balanced chemical equation, how many grams of NaN3 are required to produce 2.0 L of N2 at STP?

Answer 1

Answer:

2 NaN3 ---> 2 Na + 3 N2

(I think NaN3 is sodium azide, not sodium nitride.)

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B)

Molar mass conversion :

(40 g NaN3) x (1 mole NaN3 / 65.01 g NaN3) = 0.62 moles NaN3

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Then a mole-to-mole conversion using the balanced equation :

(0.62 moles NaN3) x (3 moles N2 / 2 moles NaN3) = 0.93 moles N2

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Then another molar mass conversion :

(0.93 moles N2) x (28.01 g N2 / 1 mole N2) = 26 g N2 (theoretical yield)