Question

Using the BDMAS rule, find the values of:
(i) 64 ÷16X(-3) + 2
(ii) -3+{(-4)÷ 4+ 1} +3​

Answer 1

Answer:

(i) -10

(ii) 0

Step-by-step explanation:

$(i) 64/16*(-3) + 2\\= 4*-3+2\\= -12+2 = -10$

$(ii) -3+{(-4)/4+ 1} +3\\= -3+(-1+1)+3\\= -3+0+3 = 0$

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