Using the concept of distance of time graph drive the reliatio v=u+at????
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To Derive: v = u + at (graphically)
Let an object of velocity (u) changes it's velocity to (v) in time (t).
Thus,
- AO = u, (= CD)
- BC = v & (= OE)
- OC = t. (= AD.)
Also let,
- BC ⊥ OX′
- BE ⊥ OY′
Here,
OE = OA + AE
→ BC = CD + BD
→ v = u + BD
→ BD = v - u ...(Eq. N)
We know,
acceleration (a) = (Change in velocity)/(Time taken)
or,
a = (v - u)/(t)
= BD/t
→ BD = at ...(Eq. S)
Thus,
v - u = at
→ v = u + at Hence, Proved...
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