Question

using the concept of distance time graph derive the relation v=u+at​

Answer 1

Explanation:

OA=BD=u

OE=CB=v

OC=AD=t

BD=BC-DC

AD is parallel to OC

BC=BD+DC=BD+OA

BC=v and OA=u

v=BD+u

BD=v-u

Slope gives you acceleration

a=change in velocity/time taken

BD/AD=BD=OC

OC=t we get a=BD/t

BD=at

BD=v-u

at=v-u

v=u-at

Hope it helps you