using the concept of slope show that the vertices ( 1,2),(-2,2),(-4,-3),(-1,-3) taken in order form a parallelogram.
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Slope=y2-y1/x2-x1
Slope of AB=2-2/-2-1=0/-3=0
Slope of BC =-3-2/-4+2=-5/-2=5/2
Slope of CD=-3+3/-1+4=0/-3=0
Slope of DA=2+3/1+1=5/4
In parallelogram opposite slopes are equal
AB=CD and BC=DA
Hence proved
Slope of AB=2-2/-2-1=0/-3=0
Slope of BC =-3-2/-4+2=-5/-2=5/2
Slope of CD=-3+3/-1+4=0/-3=0
Slope of DA=2+3/1+1=5/4
In parallelogram opposite slopes are equal
AB=CD and BC=DA
Hence proved
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