Using the different digits, find the smallest
number of 4 digits in which 9 is in tens
place]
Answers
Answer:
Step-by-step explanation:
The smallest positive integer with all different digits and 9 as the tens digit would need the smallest single digit positive integers as the remaining three digits. These are 1, 2 and 3.
To make it the smallest, we need to make the thousands digit the smallest of our three numbers, the hundreds needs to be the middle number, and the units would need to be the largest number.
This gives us 1293.
If we expand our choice of numbers to include negative numbers, we can have many smaller numbers. This time we need to look at the largest single digit positive integers to get our other three. Assuming we can’t reuse the 9 as one of them, due to the problem requiring different digits, we get the number 8, 7 and 6.
To make it the smallest negative number, we would go through the same process as before, but instead trying to make the largest positive number, then turning it into a negative. This would just mean our thousands would be the largest of our three numbers, the hundreds would again be the middle, and the units would be the smallest.
This gives us -8796.
We could go further down the rabbit hole by changing the definitions of a four digit number to include non-integer values, but if we stick to only whole numbers, those are the two possible results
Answer:
1090
(sorry what ever is in this is just filler