Math, asked by ajayprakash14, 1 month ago

Using the divisibility test determine which of the following numbers are divisible by 4 by 5 or by 9. 1) 53486​

Answers

Answered by hritikvijay547
0

Answer:

Using divisibility tests, determine which of the following numbers are divisible by 11:

Using divisibility tests, determine which of the following numbers are divisible by 11:(a) 5445 (b) 10824 (c) 7138965 (d) 70169308 (e) 10000001

Using divisibility tests, determine which of the following numbers are divisible by 11:(a) 5445 (b) 10824 (c) 7138965 (d) 70169308 (e) 10000001(f) 901153

(a) 5445

Sum of the digits at odd places = 5 + 4 = 9 Sum of the digits at even places = 4 + 5 = 9 Difference = 9 - 9 = 0 As the difference between the sum of the digits at odd places and the sum of the digits at even places is O, therefore, 5445 is divisible by 11.

(b) 10824

Sum of the digits at odd places = 4 + 8 + 1 = 13 Sum of the digits at even places = 2 + 0 = 2 Difference = 13 - 2 = 11 The difference between the sum of the digits at odd places and the sum of the digits at even places is 11, which is divisible by 11. Therefore, 10824 is divisible by 11.

(c) 7138965

Sum of the digits at odd places = 5 + 9 + 3 + 7 = 24 Sum of the digits at even places =6 + 8 + 1 = 15 Difference = 24 - 15 = 9 The difference between the sum of the digits at odd places and the sum of digits at even places is 9, which is not divisible by 11. Therefore, 7138965 is not divisible by 11.

(d) 70169308

Sum of the digits at odd places = 8 + 3 + 6 + 0 Sum of the digits at even places = 0 + 9 + 1 + 7 = 17 Difference = 17 - 17 = 0 As the difference between the sum of the digits at odd places and the sum of the digits at even places is O, therefore, 70169308 is divisible by 11.

(e) 10000001

Sum Of the digits at Odd places = 1 Sum of the digits at even places 1 Difference = 1 - 1 = 0 As the difference between the sum of the digits at odd places and the sum of the digits at even places is O, therefore, 10000001 is divisible by 11.

(f) 901153

Sum of the digits at odd places = 3 + 1 + 0 = 4 Sum Of the digits at even places = 5 + 1 + 9 = 15 Difference = 15 - 4 = 11 The difference between the sum of the digits at odd places and the sum of the digits at even places is 11, which is divisible by 11. Therefore, 901153 is divisible by 11.

Answered by babysachdeva123
1

Answer:

53486 is not divisible by 4.

53486 is not divisible by 5.

53486 is not divisible by 9.

Step-by-step explanation:

53486 is not divisible by 4 because the divisiblity test of 4 is done by taking the last two digits and dividing them from 4. If it comes in 4 table then it is divisible if it's not then it's not.

53486 - 86 = 86 ÷ 4 = 21.5 ( Should not be in decimal )

It's also not divisible from 5 because the divisiblity test of 5 is done by taking the last digit and if it is 5 or 0 then it is divisible if not so it's not divisible.

53486 - 6 ( But it should be 5 or 0 )

It's not divisible from 9 too because to check that a number is divisible from 9 we should add all the digits together and if the answer comes in 9 table it is divisible if not so it's not divisible from 9.

53486 - 5+3+4+8+6 = 26 ( Not in table of 9 )

Hope this will help you

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