Using the factor theorem, factorise x^4-10x^3+35x^2-50x+24
Answers
hola mate....
step-by-step explanation:
Given Expression: x^4+10x^3+35x^2+50x+24x
4
+10x
3
+35x
2
+50x+24
let p(x) = x^4+10x^3+35x^2+50x+24x
4
+10x
3
+35x
2
+50x+24
If a polynomial function has integer coefficients, then every rational zero will have the form
\frac{p}{q}
q
p
where p is a factor of the constant and q is a factor of the leading coefficient.
p = ±1 , ±2 , ±3 , ±4 , ±6 , ±8 , ±12 , ±24
q = ±1
Find every combination of \pm\frac{p}{q}±
q
p
.
These are the possible roots of the polynomial function.
±1 , ±2 , ±3 , ±4 , ±6 , ±8 , ±12 , ±24
So, by hint and trail,
for x = 4 we get p(4) = 0
So ( x - 4 ) is factor of p(x).
Now by dividing p(x) by (x - 4) we get
Quotient, q(x)= x³ − 6x² + 11x − 6
Again by hint and trial
for q = 3 we get q(3) = 0
Thus, Another factor is ( x - 3 )
Again diving q(x) with x - 3 we get
Quotient = x² − 3x + 2
Factorizing x² − 3x + 2 by middle term split we get,
x² − 3x + 2 = x² - 2x - x + 2 = x ( x - 2 ) - ( x - 2 )
= ( x -2 ) ( x - 1 )
Therefore, Factors of p(x) are ( x - 1 ) ( x - 2 )( x - 3 )( x - 4 )
hope it helpful for u