Question

using the figure ΔABC, prove that sin^2 teeta +cos^2 teeta =1​

Answer 1

Answer:

Consider a right-angled triangle, ΔABC, where ∠BAC=θ,

triangle ABC

By the Pythagorean theorem,

AC2+BC2=AB2

Dividing by AB2,

⇒AC2AB2+BC2AB2=AB2AB2⇒(oppositehypotenuse)2+(adjacenthypotenuse)2=AB2AB2=1

⇒sin2θ+cos2θ=1

Answer 2

Answer:

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