Using the following figure show that BD is √x.
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Step-by-step explanation:
((X+1)/2)^2 =((x-1)/2)^2 +BD^2
BD^2=((x+1)/2)^2 - ((x-1)/2)^2
BD^2=(x+x+x-x/4)*(x+1)-(x+1)
= 4x/4
BD^2 =x
BD^2=√x
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