using the formula for squaring a binomial, evaluate (103)^2
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Given (103)^2
But we can write 103 as 100+3
And also we know that (a + b)2 = a^2+2ab+b^2
By applying the above identity we get
(103)^2 = (100+3)^2= 100^2+2(100) (3) +3^2 (100+3)^2=10000+600+9=10609
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