Using the formula of (a+b)(a-b) find (i)[ 3/2m+2/3n] [3/2m-2/3n]
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Answer:
(a-b)(a+b)=a^2-b^2
so in given question
[3/2m+2/3n][3/2m-2/3n] becomes
(3/2m)^2-(2/3n)^2=
9/4m^2-4/9n^2. is the answer
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