Using the formula tan(A+B)=tanA+tanB/1-tanA.tanB.Find value of tan75.
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Solution :
Let A = 45° , B = 30°
tan 75
= tan( 45 + 30 )
= [ tan45 + tan 30 ]/[ 1 - tan45 × tan30 ]
= [ 1 + 1/√3 ]/[ 1 - 1/√3 ]
= ( √3 + 1 )/( √3 - 1 )
••••
Let A = 45° , B = 30°
tan 75
= tan( 45 + 30 )
= [ tan45 + tan 30 ]/[ 1 - tan45 × tan30 ]
= [ 1 + 1/√3 ]/[ 1 - 1/√3 ]
= ( √3 + 1 )/( √3 - 1 )
••••
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