Question

Using the given pattern, find the missing numbers:
a)12 + 22 + 22 = 32 b) 112 = 121
22 + 32 + 62 = 72 1012 = 10201
32 + 42 + 122 = 132 10012 = 1002001
42 + 52 + ---- = 212 1000012 = 1_____2_____1
52 + ---- + 302 = 312 100000012 = ______________
62 + 72 + ---- = ---

Answer 1

The sequence we have,
12 + 22 + 22 = 32
22 + 32 + 62 = 72
32 + 42 + 122 = 132
42 + 52 + 202 = 212
52 + 62 + 302 = 312
62 + 72 + 422 = 432

The next sequence,
112 = 121
1012 = 10201
10012 = 1002001
1000012 = 10000200001
100000012 = 100000020000001
The rule of this sequence is this that , if a number is given , combination of 1,2,0 , then answer of that number should be such that 1 should be at the corners.
Easiest way of writing that number is first write down the number as given except 1 then write that number repeatedly but reversely but not 2.
For ex:
1012
first step:102
second step : 10201.