Math, asked by pavithra88, 9 months ago

using the given picture find the total special offer price of fresh sweets and Bakery products to buy 1/2 kg laddu, 1 kg cake, 6 pockets of bread.​

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Answered by ChitranjanMahajan
7

Special offer price of 1 / 2 kg laddu is Rs. 98, and that of 1 kg chocolate cake and 6 packets of bread is Rs. 440 and Rs. 96 respectively.

• According to the given picture,

Price of 1 kg laddu = Rs. 245

Price of 1 kg chocolate cake = Rs. 550

Price of one packet of bread = Rs. 20

Discount on each item = 20 %

• Using the data given in the picture,

Marked price of 1 / 2 kg laddu = Rs. 245 × (1 / 2) = Rs. 245 / 2

= Rs. 122.5

• Discount given on 1 / 2 kg laddu = 20 % of Rs. 122.5

= (20 / 100) × Rs. 122.5

= (20 × Rs. 122.5) / 100

= Rs. 24.5

• Therefore, discounted price of 1 / 2 kg laddu = Marked Price of 1 / 2 kg laddu - Discount given on the marked price

=> Discounted price of 1 / 2 kg laddu = Rs. 122.5 - Rs. 24.5

= Rs. 98

  Special offer price of 1 / 2 kg laddu = Rs. 98

• Weight of chocolate cake to be bought = 1 kg

• According to the picture, marked price of 1 kg chocolate cake = Rs. 550

• Discounted price of chocolate cake = Rs. 550 - 20 % of Rs. 550

= Rs. 550 - (20 / 100) × Rs. 550

= Rs. 550 - (20 × Rs. 550) / 100

= Rs. 550 - (2 × Rs. 55)

= Rs. 550 - Rs. 110

= Rs. 440

∴   Discounted price of 1 kg chocolate cake = Rs. 440

• Number of packets of bread to be bought = 6

• According to the picture, marked price of 6 packets of bread = 6 × Rs. 20 = Rs. 120

• Discounted price of 6 packets of bread = Rs. 120 - 20 % of Rs. 120

= Rs. 120 - (20 / 100) × Rs. 120

= Rs. 120 - (20 × Rs. 120) / 100

= Rs. 120 - (2 × Rs. 12)

= Rs. 120 - Rs. 24

= Rs. 96

∴   Selling price of 6 packets of bread = Rs. 96

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