Question

Using the giving patter, find the missing numbers​

Answer 1

answer see this attachment.✨

third number = 1st number × second number

fourth number = 3rd number + 1

hope it is helpful for you ✌

Answer 2

Solution :

Given Clue :

${1}^{2} + {2}^{2} + {2}^{2} = {3}^{2}$

${2}^{2} + {3}^{2} + {6}^{2} = {7}^{2}$

${3}^{2} + {4}^{2} + {12}^{2} = {13}^{2}$

So in these three given clues we can observe that

1 × 2 = 2

So squaring these we get

1² + 2² + 2² = 3²

Same we can see that

2 × 3 brings 6

After squaring we get

2² + 3² + 6² = 7²

So according to these we will solve the rest

${4}^{2} + {5}^{2} + \boxed{ {20}^{2} } = {21}^{2}$

${5}^{2} + \boxed{ {6}^{2} }+ {30}^{2} = {31}^{2}$

The last case is is little complicated but according to solution progress we can see that 2 and 3, 3 and 4, 4 and 5

So it is increasing by 1 and we have to multiply it

${6}^{2} + {7}^{2} + \boxed{{42}^{2}} = \boxed {{43}^{2}}$

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