Question

Using the graph of f(x) = log2x below, approximate the value of y in the equation 22y = 3

Answer 1

whoch class it is if u say i can give answer according to th

Answer 2

Answer:

y=0.8

Step-by-step explanation:

Given : Using the graph of $f(x) = log_2x$

To find : Approximate the value of y in the equation $2^{2y}=3$

Solution :

We have to approximate the value of y from the equation:

$2^{2y}=3$

Taking log to the base 2 of both sides, we get:

$log_{2}(2^{2y})=log_{2}(3) \\  \\2y(log_{2}(2)= log_{2}(3) \\  \\2y=log_{2}(3) \\  \\y=  \frac{log_{2}(3)}{2}$

In order to find the value of y, we first need to find the value of $\log_2=3$  from the graph.

From the graph we can see that the value of log_{2}(3) is about 1.6.

Refer the attached figure below.

So, $y = \frac{1.6}{2}= 0.8$

Therefore, The value of y=0.8