Question

using the identity (a-b)^2 =(a^2-2ab+b^2) evaluate (289)^2​

Answer 1

Answer:

83521

Step-by-step explanation:

$289^{2}$

= $(300-1)^{2$

= $300^{2}$ - 2*300*11 + $11^{2}$

= 90000 - 6600 + 121

= 83521