using the identity (a+b)(a-b)=(a^2-b^2) evaluate the following: 10/3 × 14/3
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Solution
We use identifies
(x+a)(x+b)=x
=2
+(a+b)x+ab and x
=2
−y
=2
=(x+y)(x−y)
(i) (x+4)(x+10)
=x
2
+(4+10)x+(4)(10)
=x
2
+14x+40
(ii) (x+8)(x−10)
=x
2
+(8−10)+(8)(−10)
=x
2
−2x−80
(iii) (3x+4)(3x+5)
=(3x)
2
+(4−5)3x+(4)(−5)
=9x
2
−3x−20
(iv) (y
2
+
2
3
)(y
2
−
2
3
)
=(y
2
)
2
−(
2
3
)
2
=y
4
−
4
9
(v) (3−2x)(3+2x)
=(3)
2
−(2x)
2
=9−4x
2
Step-by-step explanation:
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