using the identity b-7 ka square
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Heya !!
We know that,
(a-b)² = a²-2ab+b²
So, (b-7)²
=> b²-14b+49
=> b²-7b-7b+49
=> b(b-7) -7(b-7)
=> (b-7) (b-7)
=> b = 7
We know that,
(a-b)² = a²-2ab+b²
So, (b-7)²
=> b²-14b+49
=> b²-7b-7b+49
=> b(b-7) -7(b-7)
=> (b-7) (b-7)
=> b = 7
aakash97:
this write answer
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