Using the identity, evaluate the following 1001square
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1001
(1000 + 1)
(a+b)^2=a^2+b^2+2ab
(1000+1)^2=1000^2+1^2+2*1000*1
=1000000+1+2000
=1002001
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(1000 + 1)
(a+b)^2=a^2+b^2+2ab
(1000+1)^2=1000^2+1^2+2*1000*1
=1000000+1+2000
=1002001
Hope it will help you!
Plz mark me as a brainlist...
Answered by
1
1001^2=(1000+1)^2
(a+b)^2=a^2 + 2ab + b^2
(1000+1)^2= (1000)^2 + 2 × 1000× 1 + 1^2
= 1000000 + 2000 + 1
=1002001
hope this answer is correct
(a+b)^2=a^2 + 2ab + b^2
(1000+1)^2= (1000)^2 + 2 × 1000× 1 + 1^2
= 1000000 + 2000 + 1
=1002001
hope this answer is correct
zainabkhan786:
plz mark me as a brainlist...
sorry
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